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If the bisectors of the opposite angles `/_Pa n d/_R` of a cyclic quadrilateral `P Q R S` intersect the corresponding cicle at `Aa n dB` respectively, then `A B` is a diameter of the circle.

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`/_P+/_R=180^@`
`1/2/_P+1/2/_R=90^@`
`/_APS+/_BRS=90^@-(1)`
`/_BRS=/_BPS-(2)`
`/_APs+/_BPS=90^@`
`/_APB=90^@`
AB is diameter of circle.
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