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Two diameters of a circle intersect each...

Two diameters of a circle intersect each other at right angles. Prove that the quadrilateral formed by joining their end-points is a square.

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Given that the two diameters `AB` and `CD` of a circle intersect each other at right angles.
`AD, DB, BC` and `CA` are joined forming a quadrilateral `ABCD`.
The diagonals are equal and bisect each other at right angles.
`ACBD` is a square.
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