A block is released from top of a smooth inclined plane.It reaches the bottom of the plane in 6 sec.The time taken by the body to cover the first half of the inclined plane is:

A block is released from top of a smooth inclined plane It reaches the bottom of the plane in sqrt2s The time taken (in second) by the body to cover Ist half of inclined plane is .

A block of mass m is released from the top of a mooth inclined plane of height h its speed at the bottom of the plane is proportion to

A block is released from the top of the smooth inclined plane of height h . Find the speed of the block as it reaches the bottom of the plane.

A block released from rest from the top of a smooth inclined plane of angle theta_1 reaches the bottom in time t_1 . The same block released from rest from the top of another smooth inclined plane of angle theta_2 reaches the bottom in time t_2 If the two inclined planes have the same height, the relation between t_1 and t_2 is

A frictionless inclined plane of length l having inclination theta is placed inside a lift which is accelerating downward with on acceleration a (ltg) . If a block is allowed to move down the inclined plane, from rest, then the time taken by the block to slide from top of the inclined plane to the bottom of the inclined plane is

A small block is freely sliding down from top of a smooth inclined plane. The block reaches bottom of inclined plane then the block describes a vertical circle of radius 0.5 m along smooth track. The minimum vertical height of inclined plane should be

A block is released on an smooth inclined plane of inclination theta . After how much time it reaches to the bottom of the plane?