The sides of a quadrangular field, taken...

The sides of a quadrangular field, taken in order are `26 m ,27 m,7m` are `24 m` respectively. The angle contained by the last two sides is a right angle. Find the area.

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Area=Area of rectangle `AECB` - Area of triangle `AED`
`=24xx26-1/2xx19xx24=624-228=396unit^2`.

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