Two chords `A B` and `C D` of a circle are parallel and a line `l` is the perpendicular bisector of `A B` . Show that `l` bisects `C Ddot`

Explanation

Given: `AB` and `CD` are two chords parallel to each other . Line `l` is the perpendicular bisector to `AB`
To prove: line `l` bisects `CD`
Proof:`AB` is parallel to `CD`
So, angle `AGH= DHG` (alternate angles) `AGH = DHG = 90^@`
As we know that line drawn from centre to the circle is perpendicular bisector to the chord.
Therefore , `l `bisects `CD`
Hence proved