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When BCl(3) is treated with water, it hy...

When `BCl_(3)` is treated with water, it hydrolyses and forms `[B(OH)_(4)]^(-)` only whereas `AlCl_(3)` in acidified aqueous solution forms `[Al(H_(2)O)_(6)]^(3+)` ion, Explain what is the hybridisation of boron and aluminium in these species?

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In trivalent state, most of the compounds being covalent are hydrolysed in water, e.g., `BCl_(3)` on hydrolysis in water form `[B(OH)_(4)]^(-)` species, the hybridisation state of B is `sp^(3)`
`{:(BCl+3H_(2)OrarrB(OH)_(3)+3HCl),(B(OH)_(3)+H_(2)Orarr[B(OH)_(4)]^(-)+H^(+)):}`
`AlCl_(3)` in acidified aqueous solution form octahedral `[Al(H_(2)O)_(6)]^(3+)` ion. In this complex, the 3d orbital of Al are involved and the hybridisation state of Al is `sp^(3)d^(2)`
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