The perimeter of a triangular field i...

The perimeter of a triangular field is 240dm. If two of its sides are 78dm and 50dm, find the length of the perpendicular on the side of length 50dm from the opposite vertex.

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AB+BC+AC=240
78+50+AC=240
AC=240-128
AC=112
AD=9
area`(/_ABC)=1/2*AD*50=25AD`
`s=(a+b+c)/2=240/2=120`
area`=sqrt(s(s-a)(s-b)(s-c)`
...

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