Find `sin``x/2``,cos``x/2`and `tan``x/2` of the following : `tanx=-4/3, `x in quadrant II`

Explanation

To find \(\sin \frac{x}{2}\), \(\cos \frac{x}{2}\), and \(\tan \frac{x}{2}\) given that \(\tan x = -\frac{4}{3}\) and \(x\) is in the second quadrant, we can follow these steps:

### Step 1: Determine \(\sin x\) and \(\cos x\)

Since \(\tan x = \frac{\sin x}{\cos x}\), we can express \(\sin x\) and \(\cos x\) in terms of a right triangle. In the second quadrant, \(\sin x\) is positive and \(\cos x\) is negative.

Let:
- Opposite side = 4 (since \(\tan x = -\frac{4}{3}\), we take the opposite side as 4)
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