If`a +b+c=9` and `a^2+b^2+c^2=35 ,` find the value of `a^3+b^3+c^3-3a b c`

Explanation

`(a+b+c)^2`=`a^2+b^2+c^2+2(ab+bc+ca)`
`(9)^2`=`35+2(ab+bc+ca)`
`46//2`=`ab+bc+ca`
`ab+bc+ca`=`23`
`a^3+b^3+c^3-3abc`=`(a+b+c)(a^2+b^2+c^2-ab-bc-ac)`
`9xx[35-23]`
=`12xx9`
=`108`