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The progress of the reaction, A ⇌ nB wit...

The progress of the reaction, A ⇌ nB with time, is presented in figure given below. Determine.

(i) The value of n,
(ii) The equilibrium constant K, and
(iii) the initial rate of conversion of A.

Text Solution

Verified by Experts

(i) 2 (ii) 1.2 (iii) `0.1" mole"^(–1) hr^(–1)`
(i) According to the figure, in the given time of 4 hours (1 to 5) concentration of A falls from 0.5 to 0.3 M, while in the same time concentration of B increases from 0.2 M to 0.6 M.
Decrease in concentration of A in 4 hours
`=0.5-0.3=0.2 M`
Increase in concentration of B in 4 hours
`=0.6-0.2=0.4 M`
Thus increase in concentration of B in a given time is twice then the decrease in concentration of A. Thus n 2.
(ii) `K=([B^(2)]_(eq))/([A]_(eq))=((0.6)^(2))/(0.3) =1.2 M`
(iii) Initial rate of conversion of A
= Change in conc. of A during 1 h
`=(0.6-0.5)/(1) =0.1" mole"^(-1) "hr"^(-1)`
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