A lamp draws a current of 1.0 A. Find the charge in coulomb used by the lamp in 60 s :

Options

A. `0.6C`
B. `60C`
C. 600C
D. `0.06C`

Explanation

To solve the problem of finding the charge in coulombs used by a lamp that draws a current of 1.0 A in 60 seconds, we can follow these steps:

### Step 1: Understand the relationship between current, charge, and time.
The current (I) is defined as the rate of flow of charge (Q) through a cross-section of a conductor. The relationship is given by the formula:
\[ I = \frac{Q}{T} \]
where:
- \( I \) is the current in amperes (A),
- \( Q \) is the charge in coulombs (C),
- \( T \) is the time in seconds (s).

### Step 2: Rearrange the formula to find charge (Q).
From the formula, we can rearrange it to solve for charge:
\[ Q = I \times T \]

### Step 3: Substitute the known values into the formula.
We know:
- \( I = 1.0 \, \text{A} \)
- \( T = 60 \, \text{s} \)

Now substituting these values into the formula:
\[ Q = 1.0 \, \text{A} \times 60 \, \text{s} \]

### Step 4: Calculate the charge (Q).
Now we perform the multiplication:
\[ Q = 1.0 \times 60 = 60 \, \text{C} \]

### Conclusion:
The charge used by the lamp in 60 seconds is:
\[ Q = 60 \, \text{C} \]