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The gas phase decomposition of N(2)O(5)"...

The gas phase decomposition of `N_(2)O_(5)" to "NO_(2) and O_(2)` is monitored by measurement of total pressure. The following data are obtained.

Find the average rate of disappearance of `N_(2)O_(5)` for the time interval between each interval and for the total time interval. [Hint : Integrated rate law is NOT to be used]

Text Solution

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`2N_(2)O_(5)(g) rarr 4NO_(2)(g) +O_(2)(g)`
Initial Pressure (at t=0) `P_(0)" "0" "0`
At equilibrium `" "P_(0)-2x" "4x" "x`
Now: `" "P_(t) =(P_(0)-2x)+4x+x`
`rArr" "x=(1)/(5) (P_(t)-P_(0))`
`P_(N_(2)O_(5))=P_(0)-2x=(1)/(3)(5P_(0)-2P_(t))`
Thus, `Delta P_(N_(2)O_(5))=(2)/(3)(P_(t1)-P_(t2))" where "P_(t2) and P_(t1)` are the total pressures at time instants `t_(2) and t_(1) (t_(2) gt t_(t1))` respectively
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The rate law for decomposition N_(2)O_(5) is rate = k[N_(2)O_(5)] What is the significance of k in the equation?

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