A polymerisation reaction is carried out at 2000 K and the same reaction is carried out at 4000 K with catalyst. The catalyst increases the potential barrier by 20 KJ but the rate of the reaction remains same. Find activation energy of the reaction.
(Assuming all other parameters to be same.)

Explanation

To find the activation energy (Ea) of the polymerization reaction, we can use the Arrhenius equation and the information provided in the question. Here’s a step-by-step solution:

### Step 1: Write the Arrhenius Equation
The Arrhenius equation is given by:
\[ k = A e^{-\frac{E_a}{RT}} \]
where:
- \( k \) = rate constant
- \( A \) = pre-exponential factor (Arrhenius constant)
...