Home
Class 12
CHEMISTRY
aA+bBrarr"Product",dx//dt=k[A]^(a)[B]^(b...

`aA+bBrarr"Product",dx//dt=k[A]^(a)[B]^(b)`. If conc. Of A is dounled, rate becomes four times. If conc. Of B is made four times, rate is doubled. What is the relation between rate of disappearance of A that B?

A

`-{d[A]//dt}=-{d[B]//dt}`

B

`-{d[A]//dt}=-{4d [B] //dt}`

C

`-{4d [A]//dt}=-{d[B]//dt}`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • Chemical Kinetics

    MOTION|Exercise Exercise -1 (Zero order reaction, 1st order reaction , 2nd order reaction & nth order reaction)|11 Videos
  • Chemical Kinetics

    MOTION|Exercise Exercise -1 (Experimental Method to calculate order)|5 Videos
  • Chemical Kinetics

    MOTION|Exercise SOLVED EXAMPLE (SUBJECTIVE)|24 Videos
  • CHEMICAL EQUILIBRIUM

    MOTION|Exercise Exercise - 4|20 Videos
  • CLASSROOM PROBLEMS

    MOTION|Exercise Electrochemistry|22 Videos

Similar Questions

Explore conceptually related problems

aB+bBrarrP,dxx//dt=k[A]^(a)8[B]^(b) . If conc. of A is doubled, rate is doubled. If B is doubled, rate becomes four times. Which is corect?

In the reaction aA+bB to products, if concentration of A is doubled (keeping B constant) the initial rate becomes four times and if B is doubled (keeping A constant), the rate becomes double. What is the rate law equation and order of reaction ?

In the reaction aA+bB to products, if concentration of A is doubled (keeping B constant) the initial rate becomes four times and if B is doubled (keeping A constant), the rate becomes double. What is the rate law equation and order of reaction ?

For a reaction 1//2A to 2B , rate of disappearance of A is related to the rate of appearance of B by the expression:

In a reaction A rarr B ,when the concentration of reactant is made "8" times,the rate got doubled.The order of reaction is "