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For the non-equilibrium process, A + B r...

For the non-equilibrium process, `A + B rarr` Product, the rate is first-order w.r.t. `A` and second order w.r.t. `B`. If `1.0 mol` each of `A` and `B` were inrofuced into `1.0 L` vessel and the initial rate was `1.0 xx 10^(-2) mol L^(-1) s^(-1)`, calculate the rate when half the reactants have been turned into Products.

A

`1.25xx10^(-3)" mol L"^(-1) s^(-1)`

B

`1.0xx10^(-2)" mol L"^(-1) s^(-1)`

C

`2.50xx10^(-3)" mol L"^(-1) s^(-1)`

D

`2.0xx10^(-2)" mol L"^(-1) s^(-1)`

Text Solution

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The correct Answer is:
A
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