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Two substances A (t(1//2) = 5 min) and B...

Two substances `A (t_(1//2) = 5 min)` and `B(t_(1//2) = 15 min)` follow first order kinetics and are taken in such a way that initially `[A] = 4[B]`. The time after which the concentration of both the substance will be equal is `5x min`. Find the value of `x`.

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MOTION-Chemical Kinetics-Exercise - 3
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  3. Two substances A (t(1//2) = 5 min) and B(t(1//2) = 15 min) follow firs...

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  4. The decomposition of a compound P, at temperature T according to the e...

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  6. For the reaction 3BrO^(-)rarr BrO(3)^(-) +2Br^(-) in an alkaline aques...

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  7. The reaction 2A + B + C rarr D + 2E is found to be first order in A, ...

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  8. The reaction A(g)+2B(g)rarrC(g)+D(g) is an elementary process. In an e...

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  9. A solution of A is mixed with an equal volume of a solution of B conta...

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  10. For the following data for the zero order reaction A rarr products. Ca...

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  12. The data given below are for the reaction of NO and Cl(2) to from NOCl...

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  13. The following data are for the reaction A+B rarr Products: {:(Conc. ...

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  14. The pressure of a gas decomposing at the surface of a solid catalyst h...

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  15. The half life period of decomposition of a compound is 50 minutes. If ...

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  16. At 600^(@)C, acetone (CH(3)COCH(3)) decomposes to ketene (CH(2) = C = ...

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  17. Catalytic decomposition of nitrous oxide by gold at 900^(@)C at an ini...

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  18. In this case we have A rarr B + C Time " "t " "prop Total press...

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  19. A rarr B + C Time " "t " "prop Total pressure of (B + C) " "P(2) " ...

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  20. A rarr B + C Time 0 t Volume of reagent V(1)" " V(2) The reagent reac...

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