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The reaction, 2NO+Br(2)rarr 2NOBr, is su...

The reaction, `2NO+Br_(2)rarr 2NOBr`, is supposed to follow the following mechanism,
(i) `NO+Br_(2) overset("fast")(hArr) NOBr_(2)`
(ii) `NOBr_(2) +NO overset(slow)(rarr)2NOBr`
suggest the rate law expression.

Text Solution

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`r=K'[NO]^(2)[Br_(2)]`
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The reaction 2NO + Br_(2) to 2NOBr , obeys the following mechanism: NO + Br_(2) overset("fast")(hArr) NOBr_(2), NOBr_(2) + NO overset("Slow")(to) 2NOBr The rate expression of the above reaction can be written as

The rate and mechamical reaction are studied in chemical kinetics. The elementary reactions are single step reaction having no mechanism. The order of reaction and molecularity are same for elementary reactions. The rate of forward reaction aA + bBrarr cC+dD is given as: rate =((dx)/(dt))=-1/a(d[A])/(dt)=-1/b(d[B])/(dt)=1/c(d[C])/(dt)=1/d(d[D])/(dt) or expression can be written as : rate =K_(1)[A]^(a)[B]^(b)-K_(2)[C]^(c )[D]^(d) . At equilibrium, rate = 0 . The constants K, K_(1), K_(2) are rate constants of respective reaction. In case of reactions governed by two or more steps reaction mechanism, the rate is given by the slowest step of mechanism. For the reaction, 2NO+Br_(2) hArr 2NOBr , the mechanism is given in two steps: (1) NO+Br_(2) overset("fast")(hArr)NOBr_(2) (2) NOBr_(2)+NO overset("slow")(rarr)2NOBr The rate expression for the reaction is:

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