Ph -CH = O + `NH_(2) - NH_(2) overset(H^(oplus))(rarr)`
(A).Product (A) is known as:

Options

A. Aldo-Oxime
B. Hydrazone
C. Hydrate
D. Phenyl hydrazone

Answer

To solve the question regarding the reaction between benzaldehyde (Ph-CHO) and hydrazine (NH2-NH2) in the presence of an acid (H+), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are benzaldehyde (Ph-CHO) and hydrazine (NH2-NH2).

2. **Understand the Reaction Type**:
- This is a condensation reaction where a carbonyl compound (benzaldehyde) reacts with hydrazine. The reaction typically involves the formation of a hydrazone.

3. **Reaction Mechanism**:
- The carbonyl group (C=O) of benzaldehyde reacts with the hydrazine. The nitrogen atom of hydrazine attacks the carbon atom of the carbonyl group, leading to the formation of a tetrahedral intermediate.

4. **Elimination of Water**:
- In the next step, a molecule of water (H2O) is eliminated. This occurs when the oxygen from the carbonyl compound (benzaldehyde) loses a hydrogen atom and the nitrogen from hydrazine loses a hydrogen atom, resulting in the formation of a double bond between carbon and nitrogen.

5. **Formation of the Product**:
- The final product formed is phenylhydrazone, which has the structure Ph-CH=N-NH2. This compound is characterized by the presence of a double bond between the carbon and nitrogen.

6. **Naming the Product**:
- The product formed from the reaction of benzaldehyde and hydrazine is specifically known as phenylhydrazone.

### Final Answer:
The product (A) is known as **Phenylhydrazone**.