Mole fraction of C(3)H(5)(OH)(3) in a s...

Mole fraction of ` C_(3)H_(5)(OH)_(3) `in a solution of ` 36 g ` of water and ` 46 g `of glycerine is :

0.46

0.36

0.2

0.4

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Calculate the mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36 g of water and 46 g of glycerine.

Mole fraction of C_(3)H_(5)(OH)_(3) in a solution of 36g of water and 46g of glycerine is:

In a binary solution, the component present in smaller proportion is called solute while the one in excess is known as solvent. The solution containing 1 mole of the solute in 1L of solution is known as one molar solution while the solution in which 1 mole of solute is dissolved in 1 kg of the solvent is called one molal solution. The ratio of the no. of moles of a particular component to the total no. of moles in the solution is known as its mole fraciton The mole fraction of glycerine C_(3)H_(5)(OH)_(3) in a solution containing 36 g of water and 46 g of glycerine is :

Mole fraction of glycerine (mol,wt=92)" in a solution containing 36g of H_(2)O and 46g of glycerine is "

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The mole fraction of CH_(3)OH in an aqueous solution is 0.02 and density is 94 "g cm"^(-3) , Determine the molality of the solution.

The mole fraction of CH_(3)OH in an aqueus solution is 0.02 and density is 0.994 g cm^(-3) . Determine the molality and molarty.

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