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Molal fraction of A vapours above te sol...

Molal fraction of A vapours above te solution in mixture of A and B `["MA"_(5)]"A"_(3)` will be
` ["Given ":"P"_("A")^(@)=100"mm Hg and"" P"_("B")^(@)=200"mm Hg"]`

A

0.4

B

0.8

C

0.25

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
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Mole fraction of vapour of A above solution in mixture of A and B(X_(A) = 0.4) will be (P_(A)^(@) = 100mm, P_(B)^(@) = 200 mm) :

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Two liquids A and B are mixed to form an ideal solution. The totol vapour pressure of the solution is 800 mm Hg. Now the mole fractions of liquid A and B are interchanged and the total vapour pressure becomes 600 mm of Hg. Calculate the vapour pressure of A and B in pure form. (Given : p_(A)^(@)-p_(B)^(@)=100 )

P_(A)=(235y -125xy)mm of HgP_(A) is partial pressure of A,x is mole fraction of B in liquid phase in the mixture of two liquids A and B and y is the mole fraction of A in vapour phase, then P_(B)^(@) in mm of Hg is:

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MOTION-LIQUID SOLUTION-EXERCISE-2 (LEVEL -I) OBJECTIVE PROBLEMS JEE MAIN
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  2. For an ideal binary liquid solutions with P(A)^(@)gtP(B)^(@), which re...

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  3. Molal fraction of A vapours above te solution in mixture of A and B ["...

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  4. Two liquid A & B form an ideal solution. What is the vapour pressure o...

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  5. Total vapour pressure of mixture of 1 mol of volatile component A(P(A^...

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  6. Which of the following is less than zero for ideal solutions ?

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  7. Identify the false statement :

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