Find the quantum number `n` corresponding to the excited state of `He^(+)` ion of on transition to the ground state that ion emits two photons in succession with wavelengths `108.5` and `30.4nm`.

Find the quantum number n corresponding to the excited state of He^(+) ion, if on transition to the ground state that ion emits two photons in succession with wave lengths 108.5 and 30.4 nm .

Find the quantum number n corresponding to the excited state of He^(Theta) ion if on transition to the ground state that ion emits two photon in succession with wavelength 108.5 and 30.4 nm

Find the quantum number n corresponding to nth excited state of He^(++) ion if on transition to the ground state the ion emits two photons in succession with wavelength 108.5 nm and 30.4 nm. The ionization energy of the hydrogen atom is 13.6 eV.

Find the quantum number n corresponding to the excited state of He^(+) ion if on transition to the ground state that ion emits two photons in succession with wavelengths state that ion emits two photons in succession with wavelengths 1026.7 and 304Å. (R = 1.096 xx 10^(7)m^(_1)

Find the quantum of the excited state of electrons in He^(+) ion which on transition to first excited state emit photons of wavelengths 108.5 nm . (R_(H)=1.09678xx10^(7) m^(-1))