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.(19)K^(40) consists of 0.012% potassium...

`._(19)K^(40)` consists of 0.012% potassium in nature. The human body contains 0.35% potassium by weight. Calculate the total radioactivity resulting from `._(19)K^(40)` decay in a 75 Kg human body. Half life of `._(19)K^(40)` is `1.3 xx 10^(9)` years

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