The sun radiates energy at the rate of `4xx10^(26)` joule `sec^(-1)`. If the energy of fusion process
`4 ._(1)^(1)H rarr ._(2)^(4)He + 2 ._(1)^(0)e`
is `27MeV`, calculated amount of hydrogen atoms that would be consumed per day for the given process.

Sun radiates energy at the rate of 3.6xx10^(26)J//s . The rate of decrease in mass of sun is (Kgs^(1)) .

The equation: 4._(1)^(1) H^(+) rarr ._(2)^(4) He^(2+) + 2e + 26MeV represnets.

If each square metre, of sun's surface radiates energy at the rate of 6.3xx10^(7) jm^(-2) s^(-1) and the Stefan's constant is 5.669xx10^(-8) Wm^(-2) K^(-4) calculate the temperature of the sun's surface, assuming Stefan's law applies to the sun's radiation.

Binding energy per nucleus of ._(1)^(2)H and ._(2)^(4)He are 1.1 MeV and 7 MeV respectively. Calculate the amount of energy released in the following process: ._(1)^(2)H + ._(1)^(2)H to ._(2)^(4)He

The ionisation energy for the Hydrogen atom in the ground state is 2.18 xx 10^(-18)J "atom"^(-1) . The energy required for the following process He^(+)(g)rarr He^(2+) (g) +e^(-) is

Calculate the energy in the reaction 2 ._(1)^(1)H + 2 ._(0)^(1)n to ._(2)^(4)He Given, H = 1.00813 amu, n = 1.00897 amu and He = 4.00388

A nuclear fusion reaction is given by ._(1)H^(2)+._(1)H^(2)rarr._(1)He^(3)+._(0)^(1)n + Q ("energy") . If 2 moles of deuterium are fused, then total released energy is

The equation 4[H^(+) rarr _(2)^(4) He^(2+) + 2e bar + 26 MeV represents

Assuming that about 20 M eV of energy is released per fusion reaction ._(1)H^(2)+._(1)H^(3)rarr._(0)n^(1)+._(2)He^(4) , the mass of ._(1)H^(2) consumed per day in a future fusion reactor of powder 1 MW would be approximately