The solubility product of calcium oxalate is `2 xx 10^(–9)` at `25^@C`. Calculate the solubility of calcium oxalate at this temperature. What will be its solubility in a 0.1 M solution of ammonium oxalate ? Assume that ammonium oxalate is completely ionized in solution. Name the effect, which operates on addition of ammonium oxalate to calcium oxalate.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Write the dissociation equation for calcium oxalate
Calcium oxalate (CaC₂O₄) dissociates in water as follows:
\[ \text{CaC}_2\text{O}_4 (s) \rightleftharpoons \text{Ca}^{2+} (aq) + \text{C}_2\text{O}_4^{2-} (aq) \]

### Step 2: Write the expression for the solubility product (Ksp)
The solubility product (Ksp) for calcium oxalate can be expressed as:
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