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0.5 gm of an oxalate was dissolved in wa...

0.5 gm of an oxalate was dissolved in water and the solution raised to 100 ml. 10 ml of this solution when titrated with N/20 `KMnO_4` required 10 ml of `KMnO_4`. Calculate the % of oxalate ion in the sample. (K = 39, Mn = 55)

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The correct Answer is:
`44%`
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