Home
Class 12
CHEMISTRY
Two Daniel cells contain the same soluti...

Two Daniel cells contain the same solution of `ZnSO_4` but differ in the `CuSO_4` solution. The emf of the cell containing 0.5 M `CuSO_4` is higher than the other cell by 0.06V. Calculate the concentration of `CuSO_4` in the other cell.

Text Solution

Verified by Experts

The correct Answer is:
`[Cu^(2+)]=0.5/10^(1//5)`
Promotional Banner

Topper's Solved these Questions

  • CLASSROOM PROBLEMS

    MOTION|Exercise Surface Chemistry|16 Videos

  • Chemical Kinetics

    MOTION|Exercise Exercise - 4 (Level - II) (SUBJECTIVE PROBLEM)|1 Videos

  • CLASSROOM PROBLEMS 1

    MOTION|Exercise THERMODYNAMICS|17 Videos

Similar Questions

Explore conceptually related problems

KI and CuSO_4 solutions when mixed give

KI and CuSO_4 solution when mixed give .

(a) Will pH value of water be same at temperature 25^(@)C and 4^(@)C ? Justify in not more than 2 or 3 sentences. (b) Two student use same stock solution of ZnSO_(4) and a solution of CuSO4. The emf of one cell is 0.03 V higher than the other. The concentration of CuSO_(4) in the cell with higher emf value is 0.5 M. Find out the concentration of CuSO_(4) in the other cell. Given : 2.303RT/F = 0.06V.

Two students use same stock solution of ZNnSO_(4) and a solution of CUSO_(4) , the emf of one cell is 0.03 V higher than that of other. The concentration of CuSO_(4) In the other cell ((2.303RT)/(F)= 0.06)

Two students use same stock solution of ZnSO_(4) and a solution of CuSO_(4) . The EMF of one cell is 0.03 higher than the other. The concentration of CuSO_(4) in the cell with higher EMF value is 0.5M . Find the concentration of CuSO_(4) in the other cell. ( Take 2.303 RT//F=0.06)

Two students use same stock solution of ZnSO_(4) and a solution of CuSO_(4) The e.m.f of one cell is 0.03V higher than the other. The conc. Of CuSO_(4) in the cell with higher e.m.f., value is 0.5M . Find outthe conc. Of CuSO_(4) in the other cell [(2.303 RT//F)=0.06] .

MOTION-CLASSROOM PROBLEMS -Electrochemistry
  1. 50 mL of 0.1 M CuSO4 solution is electrolysed using Pt electrodes with...

    Text Solution

    |

  2. An electric current is passed through electrolytic cells in series one...

    Text Solution

    |

  3. A current of 1.70A is passed trhough 300.0 mL of 0.160M solution of Zn...

    Text Solution

    |

  4. An acidic solution of Cu^(2+) salt containing 0.4g of Cu^(2+) is elect...

    Text Solution

    |

  5. (a) If E^@ (Ag^(+)//Ag) = 0.8 V and E^@ (H^(+)//H2) = 0 V, in a cell a...

    Text Solution

    |

  6. For each of the following cells : (a) Write the equation for cell pr...

    Text Solution

    |

  7. Find the electrode potentials of the following electrodes. (a) Pt, ...

    Text Solution

    |

  8. For the cell : Zn//Zn^(2+) (x M) | | Ag^(+)/Ag (y M) (a) Write Nerns...

    Text Solution

    |

  9. If excess of Zn is added to 1.0M solution of CuSO4, find the concentra...

    Text Solution

    |

  10. A cell contains two hydrogen electrodes. The negative electrode is in ...

    Text Solution

    |

  11. Find the standard electrode potential of MnO(4)^(c-)|MnO(2). The stand...

    Text Solution

    |

  12. E.M.F. of following cell is 0.265 V at 25^@C and 0.2595 V at 35^@C. Ca...

    Text Solution

    |

  13. Calculate the EMF of the following cell at 25^@C, Pt, H2 (1 atm) / H^+...

    Text Solution

    |

  14. Calculate the electrode potential at 25^@C of Cr2O7^(2–)//Cr^(3+) elec...

    Text Solution

    |

  15. Find the K(sp) of AgCl from the following data. The standard electrode...

    Text Solution

    |

  16. The standard reduction potential of the Ag^(o+)|Ag electrode at 298K i...

    Text Solution

    |

  17. Two Daniel cells contain the same solution of ZnSO4 but differ in the ...

    Text Solution

    |

  18. During the discharge of a lead storage battery, the density of sulphur...

    Text Solution

    |

  19. A test for complete removal of Cu^(2+) ions from a solution of Cu^(2+)...

    Text Solution

    |

  20. A graph is plotted between E(cell) and log .([Zn^(2+)])/([Cu^(2+)]) . ...

    Text Solution

    |