End product of this reaction is
`CH_(3)-overset(O)overset(||)C-CH_(2)-CH_(2)-CH_(2)-COOH overset(NaBH_(4))to overset(H^(+)//Delta)to`

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Answer

To determine the end product of the reaction given by the equation:

\[ \text{CH}_3-\overset{O}{\overset{||}{C}}-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{COOH} \overset{\text{NaBH}_4}{\rightarrow} \overset{H^+/\Delta}{\rightarrow} \]

we will follow these steps:

### Step 1: Identify the Reactant
The reactant is a carboxylic acid with the structure:
\[ \text{CH}_3-\overset{O}{\overset{||}{C}}-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{COOH} \]
This compound is 2-hexenoic acid.

### Step 2: Understand the Role of NaBH4
Sodium borohydride (NaBH4) is a reducing agent. It will reduce the carbonyl group (C=O) of the carboxylic acid to a primary alcohol.

### Step 3: Reduction Reaction
When NaBH4 is added to the carboxylic acid, the carbonyl carbon (C=O) is reduced to a hydroxyl group (-OH). The reaction can be summarized as follows:
\[ \text{RCOOH} + \text{NaBH}_4 \rightarrow \text{RCH}_2\text{OH} + \text{by-products} \]
In this case, the carbonyl carbon of the carboxylic acid will be converted to a primary alcohol.

### Step 4: Acid Work-Up
After the reduction, the reaction mixture is treated with an acid (H+) and heat (Δ). This step is often used to protonate the alcohol formed and to ensure that all the reactions are complete.

### Step 5: Final Product
The end product after the reduction and acid work-up will be:
\[ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{OH} \]
This compound is 1-hexanol.

### Final Answer
The end product of the reaction is 1-hexanol.

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