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The effective radius of an iron atom is ...

The effective radius of an iron atom is `1.42 Å`. It has a rock-salt structure. Calculate its density (Fe = 56)

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`rho=(4xx(56)/(N_(A)))/(a^(3))`
`sqrt(2a)=4r impliesa=(4r)/(sqrt(2))=4.016 Å`
`rho=(4xx56)/(6.022xx10^(23)xx(4.016)^(3)xx10^(-30))`
`rho=5.74 g//cm^(3)`
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