If the length of the body for `CaCl` which crystallizes into a cubic strructure with `Cl^(Θ)` ions at the corners and `Cs^(o+)` ions at the centre of the unit cell is `7 Å` and the radius of he `Cs^(o+)` ions is `1.69Å`, what is the radius of `Cl^(ɵ)` ions?

Explanation

`asqrt(3)=7`
`r_(+)r_(-)=(asqrt(3))/(2)=(7)/(2)`
`1.69+r_(-)=3.5`
`r_(-)=3.5-1.69=1.8`Å