An element A (Atomic weight =100 ) having b.c.c. structures has unit cell edge length 400 pm. Calculate the density of A. number of unit cells and number of atoms in 10 g of A.

Explanation

a = 400 pm = 4 × `10^(–8)` cm
z=2
`d=(ZM)/(a^(3)N_(A))=(2xx100)/((4xx10^(-8))^(3)xx6.23xx10^(23))=(200)/(38.54)`
5.188 `gm//cc`
In 100 gm`gm too 6.23xx10^(23)` atoms
In 10 gm `too too 6.023xx10^(22)` atoms