The unit cell of a metallic element of atomic mass `10^(8)` and density 10.5 `g/cm^(3)` is a cube with edge length of 409 PM. The structure of the crystal lattice is -
(A) fcc (B) bcc
(C) hcp (D) None of these

Explanation

(A)
`rho=(ZxxM)/(Nxxa^(3))`
Here, M=108, `N_(A)`=6.023xx10^(23)`
Put on these values and solving we get- a=409 PM=`4.09xx10^(-8)` cm.
`rho=10.5 g//cm^(3)`
n=4= number of atoms per unit cell So, The structure of the crystal lattice is fcc.