`CH_3-overset(CH_3)overset(|)underset(CH_3)underset(|)C-CH_2CH_2CH_2OH overset(H^+)to `
Alkene The alkene formed in the above reaction will be

Options

A.
B. `CH_3-overset(CH_3)overset(|)underset(CH_3)underset(|)C-CH=CH-CH_3`
C. `CH_3-overset(CH_3)overset(|)underset(CH_3)underset(|)C-CH=CH_2`
D. none of the above

Answer

To solve the question regarding the alkene formed from the given alcohol, we will follow these steps:

### Step 1: Identify the Structure of the Alcohol
The given compound is:
\[ CH_3 - C(CH_3)_2 - CH_2 - CH_2 - CH_2 - OH \]
This structure indicates that we have a tertiary alcohol due to the presence of a hydroxyl (-OH) group attached to a carbon that is connected to three other carbon atoms.

### Step 2: Dehydration Reaction
When the alcohol is treated with an acid (H⁺), a dehydration reaction occurs. This involves the loss of a water molecule (H₂O) from the alcohol, leading to the formation of a carbocation.

### Step 3: Formation of Carbocation
Upon dehydration, the -OH group is protonated, making it a better leaving group. The water molecule leaves, forming a carbocation. In this case, the carbocation formed is a primary carbocation initially, but it can undergo rearrangement to form a more stable secondary carbocation.

### Step 4: Carbocation Rearrangement
The primary carbocation can undergo a hydride shift (a rearrangement) to form a more stable secondary carbocation. This occurs as follows:
- The hydride (H⁻) from the adjacent carbon shifts to the positively charged carbon, stabilizing the carbocation.

### Step 5: Formation of Alkene
Once the more stable carbocation is formed, the next step is the elimination of a proton (H⁺) to form the alkene. The elimination can occur in two possible ways:
1. Elimination of H from the carbon adjacent to the carbocation.
2. Elimination of H from the carbon that is further away.

### Step 6: Determine the More Stable Alkene
The alkene formed from the elimination will depend on which carbon the H⁺ is removed from:
- If H⁺ is removed from the adjacent carbon, we will get one alkene.
- If H⁺ is removed from the other carbon, we will get another alkene.

### Step 7: Analyze Alkene Stability
To determine which alkene is more stable, we consider the number of alkyl groups attached to the double bond:
- More alkyl substituents on the double bond lead to greater stability due to hyperconjugation and the inductive effect.

### Conclusion
After analyzing the possible alkenes formed and their stability, the alkene with the most alkyl substituents will be the major product.

### Final Answer
The alkene formed in the reaction will be the one with the highest stability, which is:
\[ CH_3 - C(CH_3)=CH - CH_2 - CH_3 \]