`CH_3-overset(CH_3)overset(|)underset(OH)underset(|)C-overset(CH_3)overset(|)underset(OH)underset(|)C-CH_3 overset(H^+)underset(Delta)to (P)` (Major)
Major product (P) is :

Options

A. `CH-overset(O)overset(||)C-overset(CH_3)overset(|)underset(CH_3)underset(|)C-CH_3`
B. `CH_3=overset(CH_3)overset(|)C-overset(CH_3)overset(|)C-CH_3`
C.
D. `CH_3-overset(O)overset(||)C-CH_3`

Answer

To solve the problem, we need to analyze the chemical reaction involving the given compound and determine the major product (P) formed after the reaction with H+ under heat (Δ). The compound can be represented as follows:

**Structure of the Compound:**
- The compound consists of two hydroxyl (OH) groups attached to a carbon chain with methyl (CH3) groups.

### Step-by-Step Solution:

1. **Identify the Structure:**
The compound can be represented as:
\[ CH_3-CH(OH)-C(OH)-CH_3 \]
This indicates that we have a symmetrical compound with two hydroxyl groups.

2. **Protonation of Hydroxyl Groups:**
When the compound reacts with H+, one of the hydroxyl groups (OH) will get protonated, forming a better leaving group (water, H2O):
\[ CH_3-CH(OH_2^+)-C(OH)-CH_3 \]
Here, the OH group becomes OH2+, making it a good leaving group.

3. **Formation of Carbocation:**
The protonated hydroxyl group leaves, resulting in the formation of a carbocation:
\[ CH_3-CH^+-C(OH)-CH_3 + H_2O \]
This carbocation is formed at the carbon where the OH group was initially located.

4. **Methyl Shift:**
A methyl group from the adjacent carbon will migrate to the carbocation center to stabilize it:
\[ CH_3-CH^+-C(OH)-CH_3 \rightarrow CH_3-CH(CH_3)-C^+-CH_3 \]
This results in a more stable tertiary carbocation.

5. **Formation of the Major Product:**
The final step involves the deprotonation of the hydroxyl group, leading to the formation of a double bond (alkene):
\[ CH_3-C(CH_3)=C(OH)-CH_3 \]
After the loss of H+, we get the major product:
\[ CH_3-C(CH_3)=C(CH_3)-CH_3 \]

### Conclusion:
The major product (P) formed from the reaction is:
\[ \text{Major Product (P)}: CH_3-C(CH_3)=C(CH_3)-CH_3 \]