Home
Class 12
CHEMISTRY
The increasing order of the boiling poin...

The increasing order of the boiling points for the following compounds is :
(I) `C_2H_5 OH` (II) `C_2H_5Cl`
(III) `C_2H_5CH_3` (IV) `C_2H_5OCH_3`

A

`(IV) lt (III) lt (I) lt (II) `

B

`(III) lt (II) lt (I) lt (IV)`

C

` (III) lt (IV) lt (II) lt (I) `

D

`(II) lt (III) lt (IV) lt (I)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the increasing order of boiling points for the compounds given, we need to analyze the molecular structures and the intermolecular forces present in each compound. The compounds are: 1. **C2H5OH** (Ethanol) 2. **C2H5Cl** (Ethyl chloride) 3. **C2H5CH3** (Ethane) 4. **C2H5OCH3** (Dimethyl ether) ### Step 1: Identify the types of intermolecular forces - **Ethanol (C2H5OH)**: This compound can form hydrogen bonds due to the presence of the hydroxyl (-OH) group. Hydrogen bonding is a strong intermolecular force. - **Ethyl chloride (C2H5Cl)**: This compound has dipole-dipole interactions due to the electronegativity difference between carbon and chlorine, but it cannot form hydrogen bonds. - **Ethane (C2H5CH3)**: This is a hydrocarbon and has only weak London dispersion forces (van der Waals forces), which are the weakest type of intermolecular force. - **Dimethyl ether (C2H5OCH3)**: This compound has dipole-dipole interactions due to the presence of the ether oxygen, but it cannot form hydrogen bonds like alcohols. ### Step 2: Compare the boiling points based on intermolecular forces - **Ethanol** has the strongest intermolecular forces due to hydrogen bonding, leading to the highest boiling point. - **Ethyl chloride** has stronger intermolecular forces than ethane but weaker than ethanol, so it will have a boiling point lower than ethanol but higher than ethane. - **Dimethyl ether** has dipole-dipole interactions, which are stronger than the London dispersion forces in ethane but weaker than the hydrogen bonding in ethanol. - **Ethane** has the weakest intermolecular forces and thus the lowest boiling point. ### Step 3: Arrange the compounds in increasing order of boiling points Based on the analysis: 1. **C2H5CH3** (Ethane) - lowest boiling point 2. **C2H5OCH3** (Dimethyl ether) - next 3. **C2H5Cl** (Ethyl chloride) - higher than ether 4. **C2H5OH** (Ethanol) - highest boiling point ### Final Order: The increasing order of boiling points is: **C2H5CH3 < C2H5OCH3 < C2H5Cl < C2H5OH**
Promotional Banner

Topper's Solved these Questions

  • ALCOHOLS & ETHERS

    MOTION|Exercise EXERCISE -4 (LEVEL -II) PREVIOUS YEAR JEE ADVANCED|9 Videos
  • ALCOHOLS & ETHERS

    MOTION|Exercise EXERCISE -3 OBJECTIVE PROBLEMS JEE ADVANCED|17 Videos
  • ALKYI HALIDE

    MOTION|Exercise Exercise - 4 | Level-II|8 Videos

Similar Questions

Explore conceptually related problems

The increasing order of the boiling points for the following compound is : underset((I))(C_(2)H_(5))OH " " underset((II))(C_(2)H_(5))Cl " " underset((III))(C_(2)H_(5))CH_(3) " " underset((IV))(C_(2)H_(5))OCH_(3)

The correct order of boiling points of the following isomeric amines is C_4H_9NH_2,(C_2H_5)_2NH,C_2H_5N(CH_3)_2

The correct order of reactivity of the compounds (I) C_(6)H_(5)H_(2)(Br) , (II) C_(6)H_(5)CH(C_(6)H_(5))Br , (III) C_(6)H_(5)CH(CH_(3))Br , (IV) C_(6)H_(5)C(CH_(3))(C_(6)H_(5))Br in the increasing order of reactivity in S_(N^(2)) reactions is

The decreasing order of reactivity of the following compounds in S_(N)1 reactions is _________. (i) C_(6)H_(5)CH_(2)Br" " (ii) C_(6)H_(5)CH(C_(6)H_(5)Br (iii) C_(6)H_(5)CH(CH_(3)Br" "(iv) C_(6)H_(5)C(CH_(3))(C_(6)H_(5))Br

Draw resonance structures for the following (i) C_6 H_5 OH (ii) C_6 H_5 CHO (iii) C_6 H_5 - CH_(2)^(+)

The increasing order of reactivity of the following isomeric halides with Ag NO_(3) (H_(2)O+alcohol) is (I) C_(6) H_(5) -CH=CH - CH_(2) -CH_(2) -CI (II) C_(6) H_(5) -CH =CH-underset(Cl)underset(|)(C)H-CH_(3) (III) C_(6) H_(5) - underset(CI)underset(|)C =CH-CH_(2) -CH_(3) (IV) C_6H_5-underset(Cl)underset(|)overset(C_6H_5)overset(|)C-CH=CH_2

Arrange the following : (a) In decreasing order of p K_b values (I) C_2H_5 NH_2 (II) PhNHMe (III) (C_2H_5)_2 NH (IV) PhNH_2 (b) In increasing order of basic strength (I) PhNH_2 (II) PhNM_(e_2) (III) (C_2H_5)_2 NH (IV) MeNH_2 ( c)Increasing order of basic strngth (I) PhNH_2 (II) p- Nitroaniline (III) p- Toluidine (d) (I) PhNH_2 (II) PhNHMe (III) PhCH_2NH_2 ( e) In decreasing order of basic strength in gas phase. (I) C_2H_5 NH_2 (II) (C_2H_5)_2NH (III) (C_2H_5)_3N (IV) NH_3 .