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A sample of water from a large swimming ...

A sample of water from a large swimming pool has a resistance of `10000Omega` at `25^(@)C` when placed in a certain conductace cell. When filled with `0.02M KCI` solution, the cell has a resistance of `100 Omega` at `25^(@)C, 585 gm` of `NaCI` were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of `8000 Omega`.
Given: Molar conductance of `NaCI` at that concentration is `125 Omega^(-1) cm^(2) mol^(-1)` and molar conductivity of `KCI` at `0.02 M` is `200W^(-1) cm^(2) mol^(-1)`.
Volume (in Litres) of water in the pool is:

A

`1.25xx10^5`

B

1250

C

12500

D

None of these

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The correct Answer is:
A
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A sample of water from a large swimming pool has a resistance of 10000Omega at 25^(@)C when placed in a certain conductace cell. When filled with 0.02M KCI solution, the cell has a resistance of 100 Omega at 25^(@)C, 585 gm of NaCI were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Omega . Given: Molar conductance of NaCI at that concentration is 125 Omega^(-1) cm^(2) mol^(-1) and molar conductivity of KCI at 0.02 M is 200W^(-1) cm^(2) mol^(-1) . Conductivity (Scm^(-1)) of H_(2)O is:

A sample of water from a large swimming pool has a resistance of 10000Omega at 25^(@)C when placed in a certain conductace cell. When filled with 0.02M KCI solution, the cell has a resistance of 100 Omega at 25^(@)C, 585 gm of NaCI were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 8000 Omega . Given: Molar conductance of NaCI at that concentration is 125 Omega^(-1) cm^(2) mol^(-1) and molar conductivity of KCI at 0.02 M is 200W^(-1) cm^(2) mol^(-1) . Cell constant (in cm^(-1)) of conductane cell is:

A sample of water from a large swimming pool has a resistance of 9200 Omega at 25^(@)C when placed in a certain conductance cell. When filled with 0.02M KCI solution the cell has a resistance of 85 Omega at 25^(@)C. 500g of NaCI were dissolved in the pool, which was throughly stirred. A sample of this solution gave a resistance of 7600 Omega . calculate the volume of water in the pool. Given: Molar conductance of NaCI at that concentration is 126.5 Omega^(-1) cm^(2) mol^(-1) and molar conductivity of KCI at 0.02M is 138 Omega^(-1) cm^(2) mol^(-1) .

When a certain conductivity cell was filled with 0.01 M solution of KCI it had a resistance of 160 omega at 25^(@)C and when filled with 0.005 M NaOH it had a resistance of 190 omega if specific resistance of KCI solution is 700 omega cm specific conductance (omega^(-1) cm^(-1)) of NaOH solution is

A conductivity cell when filled with 0.01 M KCl has a resistance of 745 Omega at 25^(@) C . When the same cell was filled with an aqueous solution of 0.005 M CaCl_(2) solution the resistance was 874 Omega . Calculate (i) Conductivity of solution (ii) Molar conductivity of solution . [Conductivity of 0.01 M KCl = 0.141 S m^(-1) ]

A conductance cell when filled with 0.5 M KCI solution (conductivity = 6.67 xx 10^(-3) Omega^(-1) cm^(-1) ) register a resistance of 243 Omega . Its cell constant is .

A conductivity cell when filled with 0.02 M KCl (conductivity = 0.002768 Omega^(-1) cm^(-1) ) has a resistance of 457.3 Omega . What will be the equivalent conductivity of 0.05 N CaCl_(2) solution if the same cell filled with this solution has a resistance of 2020?

A conductivity cell has a cell constant of 0.5 cm^(-1) . This cell when filled with 0.01 M NaCl solution has a resistance of 384 ohms at 25^(@)C . Calculate the equivalent conductance of the given solution.

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