Home
Class 12
CHEMISTRY
The resistance of a conductivity cell fi...

The resistance of a conductivity cell filled with 0.01 N soltion of NaCl is 210 ohm at `18^(@)`C. Calculate the equivalent conductivity of the solution. The cell constant of the conductivity cell is 0.88 `cm^(–1)`|.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    MOTION|Exercise EXERCISE-4,I|30 Videos

  • ELECTROCHEMISTRY

    MOTION|Exercise EXERCISE-4,II|44 Videos

  • ELECTROCHEMISTRY

    MOTION|Exercise EXERCISE -2 (LEVEL-2)|26 Videos

  • D-BLOCK ELEMENTS

    MOTION|Exercise Exercise IV Level-II|9 Videos

  • GASEOUS STATE

    MOTION|Exercise EXERCISE-4( LEVEL-II)|19 Videos

Similar Questions

Explore conceptually related problems

The resistance of 0.01 N solution at 25^(@)C is 200 ohm. Cell constant of the conductivity cell is unity. Calculate the equivalent conductance of the solution.

Calculate the resistance of 0.01 N solution of an electrolyte whose equivalent conductivity is 420 ohm^(-1) cm^(2) equiv^(-1) . (The cell constant of the cell is 0.88 cm^(-1) )

Calculating conductivity and molar conductivity: Resistance of a conductivity cell filled with 0.1 M KCl solution is 100 Omega . If the resistance of the same cell when filled with 0.02 M KCl solutions 520 Omega and the conductivity of 0.1 KCl solution is 1.29 S m , calculate the conductivity and moalr conductivity of 0.02 M KCl solution. Strategy : Calculate the cell constant with the help of 0.01 M KCl solution (both R and kappa are Known). Use the cell constant to determine the conductivity of 0.02 M KCl solution and finally find its molar conductivity using the molarity

MOTION-ELECTROCHEMISTRY-EXERCISE-3
  1. A solution of Ni(NO(3))(2) is electrolyzed between platium electrodes...

    Text Solution

    |

  2. A current of 3.7 A is passed for 6 hrs. between Ni electrodes in 0.5 L...

    Text Solution

    |

  3. The resistance of a conductivity cell filled with 0.01 N soltion of Na...

    Text Solution

    |

  4. The molar conductivity of 0.1 M CH3COOH solution is 4.6 S cm^2 "mole"^...

    Text Solution

    |

  5. The conductivity of pure water in a conductivity cell with electrodes ...

    Text Solution

    |

  6. The conductivity of pure water in a conductivity cell with electrodes ...

    Text Solution

    |

  7. For 0.01 N KCl, the resistivity 709.22 ohm cm. Calculate the conductiv...

    Text Solution

    |

  8. A solution containing 2.08 g of anhydrours barium chloride is 400 CC o...

    Text Solution

    |

  9. For the strong electrolytes NaOH, NaCl and BaCl2 the molar ionic condu...

    Text Solution

    |

  10. Equivalent conductance of 0.01 N Na2SO4 solution is 112.4ohm^(-1)cm^2e...

    Text Solution

    |

  11. The value of .m^(^^oo) for acetic acid. If the equivalent conductivity...

    Text Solution

    |

  12. Specific conductance of saturated solution of AgBr is 8.486xx10^(-7)oh...

    Text Solution

    |

  13. Saturated solution of AgCl at 25^(@)C has specific conductance of 1.12...

    Text Solution

    |

  14. Hydrofluoric acid is a weak acid. At 25^(@)C, the molar conductivity o...

    Text Solution

    |

  15. At 25^(@)C,lamda(oo)(H^+)=3.4982xx10^(-2)S m^2mol^(-1) and lamda(oo)(O...

    Text Solution

    |

  16. The Standard reduction potential values, E^(@)(Bi^(3+)//Bi) and E^(@)(...

    Text Solution

    |

  17. The cell Pt, H(2)(1atm)|H^(+)(pH=x)|| normal calomel electrode has an ...

    Text Solution

    |

  18. Voltage of the cell Pt,H2(1 atm)|HOCN(1.3xx10^(-3)M)||Ag^(+)(0.8M)|Ag(...

    Text Solution

    |

  19. Calculate the potential of an indicator electrode versus the standard ...

    Text Solution

    |

  20. Calculate the e.m.f. of the cell Pt|H(2)(1.0atm)|CH(3)COOH (0.1M)||N...

    Text Solution

    |