Home
Class 12
CHEMISTRY
At 25^(@)C,lamda(oo)(H^+)=3.4982xx10^(-2...

At `25^(@)C,lamda_(oo)(H^+)=3.4982xx10^(-2)S m^2mol^(-1)` and `lamda_(oo)(OH^-)=1.98xx10^(-2)S m^2 mol^(-1)`
Given : Sp. Conductance `=5.7xx10^(-6)Sm^(-1)` for `H_2O` determine pH and `K_w`

Text Solution

Verified by Experts

The correct Answer is:
A, D
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    MOTION|Exercise EXERCISE-4,I|30 Videos

  • ELECTROCHEMISTRY

    MOTION|Exercise EXERCISE-4,II|44 Videos

  • ELECTROCHEMISTRY

    MOTION|Exercise EXERCISE -2 (LEVEL-2)|26 Videos

  • D-BLOCK ELEMENTS

    MOTION|Exercise Exercise IV Level-II|9 Videos

  • GASEOUS STATE

    MOTION|Exercise EXERCISE-4( LEVEL-II)|19 Videos

Similar Questions

Explore conceptually related problems

Conductivity water (prepared by repeated distillation of water containing a small quantity of NaOH and KMnO_(4)) has conductivity 5.50 xx 10^(-6) S m^(-1) . If lamda_(H+)6(0) = 3.498 S m^(2) mol^(-1) and lamda_(OH-)^(0) = 1.980 xx 10^(9-2) S m^(2) mol^(-1) , then calculated lthe ionic product of water. Strategy : Water is known to be slightly ionized as {:(,H_(2)O(1)hArr,H^(+)(aq.)+,OH^(-)(aq.)),("I.C",C,0,0),("F.C",C(1-alpha),C alpha,C alpha):} According to the law of chemical equilibrium K_(eq).xx=([H^(+)][OH^(-)])/([H_(2)O]) Since water ionizes only very slightly, the concentration of H_(2)O may be taken as constant. Thus K_(eq) xx "constant" = K_(w) = [H^(+)][OH^(-)] The product of the concentrationof H^(+) and OH^(-) ions expressed in mol L^(-1) is known as ionic product of water (K_(w)) : (K_(w)) = [H^(+)][OH^(-)] = (Calpha)(Calpha) = C^(2)alpha^(2) Thus we need to find C and alpha

Rate constant k = 1.2 xx 10^(3) mol^(-1) L s^(-1) and E_(a) = 2.0 xx 10^(2) kJ mol^(-1) . When T rarr oo :

We have taken a saturated solution of AgBr.K_(sp) of AgBr is 12xx10^(-14) . If 10^(-7) mole of AgNO_(3) are added to 1 mitre of this solutio then the conductivity of this solution in terms of 10^(-7)Sm^(-1) units will be [given lamda((Ag^(+)))^(@)=4xx10^(-3)Sm^(2)mol^(-1)lamda_((Br^(-)))^(@)=6xx10^(-3)Sm^(2)mol^(-1). lamda_((NO_(3)^(-)))^(@)=5xx10^(-3)Smmol^(-1)) (A). 39 (B). 55 (C). 15 (D). 41

We have taken a saturated solution of AgBr,K_(sp) of AgBr is 12xx10^(-14) . If 10^(-7) "mole" of AgNO_(3) are added to 1 litre of this solution then the conductivity of this solution in terms of 10^(-7) Sm^(-1) units will be: [Given: lambda_((Ag^(+)))^(@)=4xx10^(-3)Sm^(2)"mol"^(-1),lambda_((Br^(-)))^(@)=6xx10^(-3) S m^(2) "mol"^(-1),lambda_((NO_(3)^(-)))^(@)=5xx10^(-3)Sm^(2) "mol"^(-1) ]

We have taken a saturated solution of AgBr , whose K_(sp) is 12xx10^(-14). If 10^(-7)M of AgNO_(3) are added to 1L of this solutino, find the conductivity ( specific conductance ) of the solution in terms of 10^(-7)S m^(-1) units. Given : lambda^(@)._((Ag^(o+)))=6xx10^(-3)S m^(2) mol^(-1) lambda^(@)._((Br^(c-)))=8xx10^(-3)S m^(2)mol^(-1) lambda^(@)._((NO_(3)^(C-)))=7XX10^(-3)S m^(2) mol^(-1)

Given lamda^(oo) [1//2 Mg^(2+)] = 53.06 ohm^(-1) cm^(2) mol^(-1) lamda^(oo) [1//2 SO_(4)^(2-)] = 80 ohm^(-1) cm^(2) mol^(-1) lamda^(oo) [1//3 Al^(3+)] = 63 ohm^(-1) cm^(2) mol^(-1) Calculate the values of Lamda_(m)^(oo) [Al_(2) (SO_(4))_(3)] and Lamda^(oo) [Mg SO_(4)]

Hydrofluoric acid is a weak acid. At 25^(@)C , the molar conductivity of 0.002 M HF is 176.2 ohm^(-1) cm^(2) mol^(-1) . If its Lamda_(m)^(oo) = 405.2 ohm^(-1) cm^(2) mol^(-1) , calculate its degree of dissociation and equilibrium constant at the given concentration.

MOTION-ELECTROCHEMISTRY-EXERCISE-3
  1. Saturated solution of AgCl at 25^(@)C has specific conductance of 1.12...

    Text Solution

    |

  2. Hydrofluoric acid is a weak acid. At 25^(@)C, the molar conductivity o...

    Text Solution

    |

  3. At 25^(@)C,lamda(oo)(H^+)=3.4982xx10^(-2)S m^2mol^(-1) and lamda(oo)(O...

    Text Solution

    |

  4. The Standard reduction potential values, E^(@)(Bi^(3+)//Bi) and E^(@)(...

    Text Solution

    |

  5. The cell Pt, H(2)(1atm)|H^(+)(pH=x)|| normal calomel electrode has an ...

    Text Solution

    |

  6. Voltage of the cell Pt,H2(1 atm)|HOCN(1.3xx10^(-3)M)||Ag^(+)(0.8M)|Ag(...

    Text Solution

    |

  7. Calculate the potential of an indicator electrode versus the standard ...

    Text Solution

    |

  8. Calculate the e.m.f. of the cell Pt|H(2)(1.0atm)|CH(3)COOH (0.1M)||N...

    Text Solution

    |

  9. The Edison storage cell is represented as : Fe(s)|FeO(s)|KOH(aq)|Ni(...

    Text Solution

    |

  10. The Edison storage cell is represented as : Fe(s)|FeO(s)|KOH(aq)|Ni(...

    Text Solution

    |

  11. The Edison storage cell is represented as Fe(s)|FeO(s)|KOH(aq)|Ni2O3...

    Text Solution

    |

  12. The standard reduction potential for Cu^(2+)|Cu is +0.34V. Calculate t...

    Text Solution

    |

  13. Determine the degree of hydrolysis and hydrolysis constant of aniline ...

    Text Solution

    |

  14. The emf of the cell, Pt|H2(1 atm),|H^+(0.1M,30ml)||Ag^+(0.8M)|Ag is 0....

    Text Solution

    |

  15. The emf of the cell Ag|AgI|KI(0.05M)||AgNO3(0.05M)|Ag is 0.788 V. Ca...

    Text Solution

    |

  16. Consider the cell AG|AgBr(s)|Br^(-)||AgCI(s)|CI^(-)|Ag at 25^(@)C. The...

    Text Solution

    |

  17. The pK(sp) of AgI is 16.07 if the E^(@) value for Ag^(+)//Ag is 0.7991...

    Text Solution

    |

  18. For the galvanic cell : Ag|AgCl(s)),KCl(0.2M)||KBr(0.001M),AgBr(s)|A...

    Text Solution

    |

  19. Given E^0=-0.268V for the Cl^-|PbCl2|Pb couple and -0.126 V for the Pb...

    Text Solution

    |

  20. Calculate the voltage E of the cell at 25^(@)C Mn(s) |Mn(OH(2))(s)|M...

    Text Solution

    |