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Estimate the cell potential of a Daniel ...

Estimate the cell potential of a Daniel cell having `1.0Zn^(++)` and originally having `1.0M Cu^(++)` after sufficient `NH_(3)` has been added to the cathode compartment to make `NH_(3)` concentration `2.0M`. Given `K_(f)` for `[Cu(NH_(4))_(4)]^(2+) = 1xx 10^(12), E^(@)` for the reaction, `Zn +Cu^(2+) rarr Zn^(2+) +Cu` is `1.1V`

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Estimate the cell potential of a Daniel cell having 1.0 M Zn^(++) and originally having 1.0M Cu^(++) after sufficient NH_(3) has been added to the cathode compartment to make NH_(3) concentration 2.0M . Given K_(f) for [Cu(NH_(4))_(4)]^(2+) = 1xx 10^(12), E^(@) for the reaction, Zn +Cu^(2+) rarr Zn^(2+) +Cu is 1.1V

The standard reduction potential E^(@) , for the half reaction are : {:(Zn rarr Zn^(2+) + 2e^(-),,,E^(@) = 0.76 V),(Cu rarr Cu^(2+) + 2e^(-),,,E^(@) = 0.34 V):} The emf for the cell reaction, Zn(s)+Cu^(2+) rarr Zn^(2+) + Cu(s) is :

The standard potential E^(@) for the half reactions are as : Zn rarr Zn^(2+) + 2e^(-), E^(@) = 0.76V Cu rarr Cu^(2+) +2e^(-) , E^(@) = -0.34 V The standard cell voltage for the cell reaction is ? Zn +Cu^(2) rarr Zn ^(2+) +Cu

The measured e.m.f. at 25^(@)C for the cell reaction , Zn(S)+Cu^(2+)(1.0 M)to Cu(s) +Zn^(2+) (0.1 M) is 1.3 volt, Calculate E^(@) for the cell reaction.

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