Home
Class 12
CHEMISTRY
Determine at 298 for cell: Pt|Q, QH(2)...

Determine at `298` for cell:
`Pt|Q, QH_(2), H^(+) ||1M KCI |Hg_(2)CI_(2)|Hg(l)|Pt`
(a) It's emf when `pH = 5.0`
(b) the `pH` when `E_(cell) = 0`
(c) the positive electrode when `pH = 7.5`
given `E_(RP(RHS))^(@) = 0.28, E_(RP(LHS))^(@) = 0.699`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    MOTION|Exercise EXERCISE-4,I|30 Videos

  • ELECTROCHEMISTRY

    MOTION|Exercise EXERCISE-4,II|44 Videos

  • ELECTROCHEMISTRY

    MOTION|Exercise EXERCISE -2 (LEVEL-2)|26 Videos

  • D-BLOCK ELEMENTS

    MOTION|Exercise Exercise IV Level-II|9 Videos

  • GASEOUS STATE

    MOTION|Exercise EXERCISE-4( LEVEL-II)|19 Videos

Similar Questions

Explore conceptually related problems

The cell Pt|H_(2)(g,01 bar) |H^(+)(aq),pH=x||Cl^(-)(1M)|Hg_(2)Cl_(2)|Hg|Pt has emf of 0.5755 V at 25^(@)C the SOP of calomel electrode is -0.28V then pH of the solution will be

For the cell: Pt|Hg(l)|Hg_(2)Cl_(2)(s)|KCl(1 M)||H^(+)|Q|H_(2)Q|Pt E_(cell) = 0.1239 V at 298 K, hence, pH of cathodic compartment is: [Given: E_(Calomel,Rp)^(@) = 0.28 V, E_(Q|H_(2)Q)^(@) = +0.699 V]

The value of E_("cell") of hydrogen electrode at pH=0 298 K and 1 atm, is

Find EMF of cell Pt |H_(2) | H^(+)(pH = 5) || H^(+) (pH =7) | H_(2)| Pt. Given that (2.303 RT)/(F) = 0.06

The reduction electrode potential E of 0.1 M solutoin of M^(+) "ions" (E_(RP)^(@)=-2.36 V) is

Calculate pH of the half cell : Pt,H_(2)(1 atm)|H_(2)SO_(4)" "E^(c-)=-0.3V

For the cell Pt||H_2(0.4atm)|H^+(pH=1)||(H^+(pH=2)|H_2(0.1atm)|Pt The measured potential at 25^(@)C is

MOTION-ELECTROCHEMISTRY-EXERCISE-3
  1. The overall formation constant for the reacction of 6 mol of CN^- with...

    Text Solution

    |

  2. Calculate E^0 for the following reactions at 298K, Ag(NH3)2^+ +e^- ...

    Text Solution

    |

  3. Calculate the equilibrium constant for the reaction: 3Sn(s) +2Cr(2)O...

    Text Solution

    |

  4. Calculate the equilibrium concentration of all ions in an ideal soluti...

    Text Solution

    |

  5. One of the methods of preparation of per disulphuric acid, H(2)S(2)O(8...

    Text Solution

    |

  6. A current of 3 amp was passed for 2 hour through a solution of CuSO4 ,...

    Text Solution

    |

  7. An acidic solution of Cu^(2+) salt contaning 0.4 of Cu^(2+) is electro...

    Text Solution

    |

  8. In the refining of silver by electrolytic method what will be the weig...

    Text Solution

    |

  9. Dal lake has water 8.2 xx 10^(12)litre approximately. A power reactor ...

    Text Solution

    |

  10. A lead storage cell is discharged which causes the H(2)SO(4) electroly...

    Text Solution

    |

  11. Determine at 298 for cell: Pt|Q, QH(2), H^(+) ||1M KCI |Hg(2)CI(2)|H...

    Text Solution

    |

  12. Determine at 298 for cell: Pt|Q, QH(2), H^(+) ||1M KCI |Hg(2)CI(2)|H...

    Text Solution

    |

  13. Determine at 298 for cell: Pt|Q, QH(2), H^(+) ||1M KCI |Hg(2)CI(2)|H...

    Text Solution

    |

  14. Calculate the cell potential of a cell having reaction: AgS+2e^- <impl...

    Text Solution

    |

  15. The equivalent conductance of 0.10 N solution of MgCl2 is 97.1 mho cm2...

    Text Solution

    |

  16. A dilute aqueous solution of KCI was placed between two electrodes 10 ...

    Text Solution

    |

  17. When a solution for specific conductance 1.342 ohm^(-1)"metre"^(-1) wa...

    Text Solution

    |

  18. The specific conductance at 25^(@)C of a saturated solution of SrSO(4)...

    Text Solution

    |

  19. Calculate the solubility product of Co(2)[Fe(CN)(6)] in water at 25^(@...

    Text Solution

    |

  20. In two vessels each containing 500 ml water, 0.5m mol of aniline (K(b)...

    Text Solution

    |