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We have taken a saturated solution of Ag...

We have taken a saturated solution of `AgBr.K_(sp)` of AgBr is `12xx10^(-14)`.If `10^-7` mole of `AgNO_3` are added to 1 litre of this solution find conductivity (specific conductance) of this solution in terms of `10^-7Sm^-1"mole"^-1`.
[Given ,`lambda_(Ag^+)^0=6xx10^-3Sm^2mol^-1`, `lambda_(Br^-)^0=8xx10^-3Sm^2mol^-1`, `lambda_(NO_3^-)^0=7xx10^-2Sm^2mol^-1`

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The correct Answer is:
`55Sm^(-1)`
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We have taken a saturated solution of AgBr.K_(sp) of AgBr is 12xx10^(-14) . If 10^(-7) mole of AgNO_(3) are added to 1 mitre of this solutio then the conductivity of this solution in terms of 10^(-7)Sm^(-1) units will be [given lamda((Ag^(+)))^(@)=4xx10^(-3)Sm^(2)mol^(-1)lamda_((Br^(-)))^(@)=6xx10^(-3)Sm^(2)mol^(-1). lamda_((NO_(3)^(-)))^(@)=5xx10^(-3)Smmol^(-1)) (A). 39 (B). 55 (C). 15 (D). 41

We have taken a saturated solution of AgBr,K_(sp) of AgBr is 12xx10^(-14) . If 10^(-7) "mole" of AgNO_(3) are added to 1 litre of this solution then the conductivity of this solution in terms of 10^(-7) Sm^(-1) units will be: [Given: lambda_((Ag^(+)))^(@)=4xx10^(-3)Sm^(2)"mol"^(-1),lambda_((Br^(-)))^(@)=6xx10^(-3) S m^(2) "mol"^(-1),lambda_((NO_(3)^(-)))^(@)=5xx10^(-3)Sm^(2) "mol"^(-1) ]

We have taken a saturated solution of AgBr , whose K_(sp) is 12xx10^(-14). If 10^(-7)M of AgNO_(3) are added to 1L of this solutino, find the conductivity ( specific conductance ) of the solution in terms of 10^(-7)S m^(-1) units. Given : lambda^(@)._((Ag^(o+)))=6xx10^(-3)S m^(2) mol^(-1) lambda^(@)._((Br^(c-)))=8xx10^(-3)S m^(2)mol^(-1) lambda^(@)._((NO_(3)^(C-)))=7XX10^(-3)S m^(2) mol^(-1)

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At 298K the conductivity of a saturated solution of AgCl in water is 2.6times10^(-6)Scm^(-1) .Its solubility product at 298K (given : lambda^(oo) ( Ag^(+) )=63.0 Scm^(2)mol^(-1) lambda^(oo) (Cl^(-)) =67.0 Scm^(2)mol^(-1) )

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