A carbon compound A forms B with sodium metal and again A forms C with `PCl_(5)` but B and C form diethylether. Therefore A, B & C are -

Options

A. `C_(2)H_(5)OH, C_(2)H_(5) ONa, C_(2)H_(5)Cl`
B. `C_(2)H_(5)Cl, C_(2)H_(5) ONa, C_(2)H_(5) OH`
C. `C_(2)H_(5)OH, C_(2)H_(6) , C_(2)H_(5)Cl`
D. `C_(2)H_(5)OH, C_(2)H_(5) Cl, C_(2)H_(5)ONa`

Answer

To solve the problem, we need to identify the compounds A, B, and C based on the given reactions and their properties.

### Step-by-Step Solution:

1. **Identify Compound A**:
- The question states that compound A reacts with sodium metal to form compound B. A common reaction of alcohols with sodium metal is the formation of sodium alkoxide.
- Let's assume A is ethanol (C2H5OH).

2. **Reaction of A with Sodium**:
- When ethanol (C2H5OH) reacts with sodium (Na), it forms sodium ethoxide (C2H5ONa) and hydrogen gas (H2):
\[ 2 \text{C2H5OH} + 2 \text{Na} \rightarrow 2 \text{C2H5ONa} + \text{H2} \]
- Here, sodium ethoxide (C2H5ONa) is compound B.

3. **Identify Compound C**:
- The question also states that A reacts with PCl5 to form compound C. When ethanol reacts with phosphorus pentachloride (PCl5), it undergoes nucleophilic substitution where the hydroxyl group (OH) is replaced by a chlorine atom (Cl).
- The reaction can be represented as:
\[ \text{C2H5OH} + \text{PCl5} \rightarrow \text{C2H5Cl} + \text{POCl3} + \text{HCl} \]
- Here, C2H5Cl is compound C.

4. **Formation of Diethyl Ether**:
- The problem states that compounds B and C react to form diethyl ether (C2H5-O-C2H5).
- The reaction between sodium ethoxide (B) and ethyl chloride (C) can be represented as:
\[ \text{C2H5ONa} + \text{C2H5Cl} \rightarrow \text{C2H5-O-C2H5} + \text{NaCl} \]
- This reaction is known as Williamson's synthesis, which produces diethyl ether.

5. **Conclusion**:
- Therefore, we have identified:
- **A**: Ethanol (C2H5OH)
- **B**: Sodium ethoxide (C2H5ONa)
- **C**: Ethyl chloride (C2H5Cl)

### Final Answer:
- A = Ethanol (C2H5OH)
- B = Sodium ethoxide (C2H5ONa)
- C = Ethyl chloride (C2H5Cl)