Reaction of ethyl bromide and silver acetate gives –

Options

A. Ethyl ethanoate
B. Methyl ethanoate
C. Ethanoic anhydride
D. 2-Butanone

Answer

To determine the product of the reaction between ethyl bromide (C2H5Br) and silver acetate (AgOAc), we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are ethyl bromide (C2H5Br) and silver acetate (AgOAc).

### Step 2: Understand the Role of Silver Acetate
Silver acetate dissociates into silver ions (Ag+) and acetate ions (CH3COO-). The acetate ion acts as a nucleophile in this reaction.

### Step 3: Nucleophilic Substitution Mechanism
In a nucleophilic substitution reaction, the nucleophile (acetate ion) attacks the carbon atom that is bonded to the leaving group (bromine in this case). The bromine atom leaves as bromide ion (Br-).

### Step 4: Write the Reaction
The nucleophilic attack can be represented as follows:
\[ \text{C2H5Br} + \text{CH3COO}^- \rightarrow \text{C2H5OCOCH3} + \text{Br}^- \]

### Step 5: Identify the Product
The product formed from this reaction is ethyl acetate (also known as ethanoate), which has the structure:
\[ \text{CH3COOCH2CH3} \]

### Step 6: Finalize the Answer
Thus, the reaction of ethyl bromide with silver acetate produces ethyl acetate (C2H5OCOCH3).

### Final Answer:
The reaction of ethyl bromide and silver acetate gives ethyl acetate (C2H5OCOCH3).

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