Reaction Reaction rate of reaction
`{:((A),HO^(Ө)+R-CH_(2)-Irarr,(P)1),((B),HO^(Ө)+R-CH_(2)-Brrarr, (Q)200),((B),HO^(Ө)+R-CH_(2)-CIrarr, (R)10000),((D),HO^(Ө)+R-CH_(2)-Frarr, (S)30000):}`

Answer

To solve the problem of matching the reaction rates with the corresponding reactions, we need to analyze the leaving groups present in each reaction. The leaving group is crucial in determining the rate of the reaction. Here’s a step-by-step solution:

### Step 1: Identify the Leaving Groups
In the reactions provided, the leaving groups are:
- (A) Iodine (I)
- (B) Bromine (Br)
- (C) Chlorine (Cl)
- (D) Fluorine (F)

### Step 2: Rank the Leaving Groups
The effectiveness of a leaving group is determined by its ability to stabilize the negative charge after leaving. The general order of leaving group ability from best to worst is:
1. Iodine (I) - best leaving group
2. Bromine (Br)
3. Chlorine (Cl)
4. Fluorine (F) - worst leaving group

### Step 3: Assign Reaction Rates Based on Leaving Groups
Now, we can assign the reaction rates (P, Q, R, S) to the reactions (A, B, C, D) based on the ranking of the leaving groups:
- (A) with Iodine (I) will have the highest rate, so it corresponds to (S) 30,000.
- (B) with Bromine (Br) will have the next highest rate, corresponding to (R) 10,000.
- (C) with Chlorine (Cl) will have a lower rate, corresponding to (Q) 200.
- (D) with Fluorine (F) will have the lowest rate, corresponding to (P) 1.

### Step 4: Final Matching
Based on the analysis:
- (A) Iodine (I) → (S) 30,000
- (B) Bromine (Br) → (R) 10,000
- (C) Chlorine (Cl) → (Q) 200
- (D) Fluorine (F) → (P) 1

### Summary of the Final Order
The final order of reaction rates based on the leaving groups is:
- A → S (30,000)
- B → R (10,000)
- C → Q (200)
- D → P (1)