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Find the domain of definitions of the fu...

Find the domain of definitions of the functions
(Read the symbols [*] and {*} as greatestintegers and fractional part functions respectively.)
`f(x) = sqrt((5x - 6-x^(2)) [{ln {x}}]) + sqrt((7x -5-2x^(2))) + (ln ((7)/(2) - x))^(-1)`

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To find the domain of the function \[ f(x) = \sqrt{(5x - 6 - x^2) \lfloor \ln{x} \rfloor} + \sqrt{(7x - 5 - 2x^2)} + \left( \ln{\left(\frac{7}{2} - x\right)} \right)^{-1} \] we need to analyze each component of the function to determine where it is defined. ### Step 1: Analyze the first term \(\sqrt{(5x - 6 - x^2) \lfloor \ln{x} \rfloor}\) 1. **Condition for the square root to be defined**: \[ (5x - 6 - x^2) \lfloor \ln{x} \rfloor \geq 0 \] This means both \(5x - 6 - x^2 \geq 0\) and \(\lfloor \ln{x} \rfloor \geq 0\) must hold true. 2. **Solve \(5x - 6 - x^2 \geq 0\)**: Rearranging gives: \[ -x^2 + 5x - 6 \geq 0 \implies x^2 - 5x + 6 \leq 0 \] Factoring: \[ (x - 2)(x - 3) \leq 0 \] The solution to this inequality is: \[ x \in [2, 3] \] 3. **Condition for \(\lfloor \ln{x} \rfloor \geq 0\)**: This implies: \[ \ln{x} \geq 0 \implies x \geq 1 \] Combining these two conditions, we have: \[ x \in [2, 3] \] ### Step 2: Analyze the second term \(\sqrt{(7x - 5 - 2x^2)}\) 1. **Condition for the square root to be defined**: \[ 7x - 5 - 2x^2 \geq 0 \] Rearranging gives: \[ -2x^2 + 7x - 5 \geq 0 \implies 2x^2 - 7x + 5 \leq 0 \] Factoring: \[ (2x - 5)(x - 1) \leq 0 \] The solution to this inequality is: \[ x \in [1, \frac{5}{2}] \] ### Step 3: Analyze the third term \((\ln{\left(\frac{7}{2} - x\right)})^{-1}\) 1. **Condition for the logarithm to be defined**: \[ \frac{7}{2} - x > 0 \implies x < \frac{7}{2} \] ### Step 4: Combine all conditions Now we need to combine the intervals obtained from each part: - From the first term, we have \(x \in [2, 3]\). - From the second term, we have \(x \in [1, \frac{5}{2}]\). - From the third term, we have \(x < \frac{7}{2}\). The intersection of these intervals is: \[ x \in [2, \frac{5}{2}] \] ### Final Domain Thus, the final domain of the function \(f(x)\) is: \[ \boxed{[2, \frac{5}{2}]} \]
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