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Let f:[-1,oo] in [-1,oo] be a function g...

Let `f:[-1,oo] in [-1,oo]` be a function given `f(x)=(x+1)^(2)-1, x ge -1`
Statement-1: The set `[x:f(x)=f^(-1)(x)]={0,1}`
Statement-2: f is a bijection.

A

f is one - one but not onto R

B

f is onto R but not one-one

C

f is one- one and onto R

D

f is neither one-one nor onto R

Text Solution

Verified by Experts

The correct Answer is:
B
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