In a family of 3 children, the probability of having at least one boy is `7/8` `1/8` `5/8` `3/4`

Explanation

All possible outcomes are BBB, BBG,BGB, GBB,BGG,GBG, GGB, GGG.
Number of all possible outcomes = 8.
Let E be the event of having at least one boy.
Then, E contains GGB, GBG, BGG,BBG,BGB,GBB,BBB.
Number of cases favourable to E = 7.
` :. ` required probability ` P(E ) = 7/8`.