The mass of a lift if 600kg and it is moving upwards with a uniform acceleration of `2m//s^(2)`. Then the tension in the cable of the lift is `:`

Options

A. 7200 N
B. 5900 N
C. 4700 N
D. zero N

Answer

To find the tension in the cable of a lift moving upwards with a uniform acceleration, we can follow these steps:

### Step-by-step Solution:

1. **Identify the Given Values:**
- Mass of the lift, \( m = 600 \, \text{kg} \)
- Acceleration of the lift, \( a = 2 \, \text{m/s}^2 \)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \) (approximately)

2. **Calculate the Weight of the Lift:**
The weight \( W \) of the lift can be calculated using the formula:
\[ W = m \cdot g \]
Substituting the values:
\[ W = 600 \, \text{kg} \cdot 10 \, \text{m/s}^2 = 6000 \, \text{N} \]

3. **Apply Newton's Second Law:**
According to Newton's second law, the net force \( F_{\text{net}} \) acting on the lift can be expressed as:
\[ F_{\text{net}} = m \cdot a \]
Substituting the values:
\[ F_{\text{net}} = 600 \, \text{kg} \cdot 2 \, \text{m/s}^2 = 1200 \, \text{N} \]

4. **Determine the Tension in the Cable:**
The tension \( T \) in the cable must overcome both the weight of the lift and provide the additional force required for the upward acceleration. Therefore, we can write:
\[ T = W + F_{\text{net}} \]
Substituting the values we calculated:
\[ T = 6000 \, \text{N} + 1200 \, \text{N} = 7200 \, \text{N} \]

5. **Final Answer:**
The tension in the cable of the lift is:
\[ T = 7200 \, \text{N} \]