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If rotational kinetic energy is 50% of t...

If rotational kinetic energy is `50%` of total kinetic energy then the body will be

A

ring

B

cylinder

C

hollow sphere

D

solid sphere

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the relationship between the rotational kinetic energy and the total kinetic energy of a body in motion. The key is to find out which body has its rotational kinetic energy equal to 50% of the total kinetic energy. ### Step-by-Step Solution: 1. **Understanding Kinetic Energy**: - The total kinetic energy (TKE) of a rolling body is the sum of its translational kinetic energy (TKE_trans) and rotational kinetic energy (TKE_rot). - The formulas are: - TKE_rot = (1/2) I ω² - TKE_trans = (1/2) m v² - Therefore, TKE = TKE_rot + TKE_trans = (1/2) I ω² + (1/2) m v² 2. **Given Condition**: - We are given that the rotational kinetic energy is 50% of the total kinetic energy: \[ \frac{TKE_{rot}}{TKE} = \frac{1}{2} \] - This implies: \[ TKE_{rot} = \frac{1}{2} TKE \] 3. **Substituting the Formulas**: - We can substitute the expressions for kinetic energies: \[ \frac{\frac{1}{2} I ω²}{\frac{1}{2} I ω² + \frac{1}{2} m v²} = \frac{1}{2} \] - Simplifying this gives: \[ \frac{I ω²}{I ω² + m v²} = \frac{1}{2} \] 4. **Cross-Multiplying**: - Cross-multiplying gives: \[ 2 I ω² = I ω² + m v² \] - Rearranging this leads to: \[ I ω² = m v² \] 5. **Relating v and ω**: - For a rolling object without slipping, the relationship between linear velocity (v) and angular velocity (ω) is: \[ v = r ω \] - Substituting this into the equation gives: \[ I ω² = m (r ω)² \] - Simplifying leads to: \[ I = m r² \] 6. **Finding Moment of Inertia**: - Now we will check the moment of inertia for different shapes: - Ring: \( I = m r² \) - Cylinder: \( I = \frac{1}{2} m r² \) - Hollow Sphere: \( I = \frac{2}{3} m r² \) - Solid Sphere: \( I = \frac{2}{5} m r² \) 7. **Checking Each Body**: - For the ring: \[ \frac{I}{mr²} = 1 \quad \text{(This satisfies the condition)} \] - For the cylinder: \[ \frac{I}{mr²} = \frac{1}{2} \quad \text{(This does not satisfy)} \] - For the hollow sphere: \[ \frac{I}{mr²} = \frac{2}{3} \quad \text{(This does not satisfy)} \] - For the solid sphere: \[ \frac{I}{mr²} = \frac{2}{5} \quad \text{(This does not satisfy)} \] 8. **Conclusion**: - The only body for which the rotational kinetic energy is 50% of the total kinetic energy is the **ring**. ### Final Answer: The body will be a **ring**.
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