" A wire of length L and resistance "R" is stretched to get the radius of cross-section halved.What is the new resistance "

A given piece of wire of length l and radius r and resistance R is stretched uniformly to wire of radius (r)/(2) .Its new resistance is:

A wire of resistance 2Omega is stretched so that its radius is halved. Determine its new resistance.

A metallic wire of length l and resistance 5 Omega is stretched to double its length. Find its new resistivity and new resistance. Assume that there is no change in the density on the stretching.

A given piece of wire oflength I, cross sectional area and resistance R is stretched uniformly to a wire oflength 21. What is the new resistance?

A wire of resistance 1 Omega is stretched to double its length. What is the new resistance ?

A wire of resistance 4 Omega is stretched to twice its original length. In the process of stretching, its area of cross-section gets halved. Now, the resistance of the wire is

A wire of resistance R is stretched to thrice its original length keeping the volume constant. Calculate its new resistance.

A wire of 10 Omega resistance is stretched to thrice its original length. What will be its (i) new resistivity and (ii) new resistance?

A given wire having resistance R is stretched so as to reduce its diameter to half of its previous value. What will be its new resistance and resistivity?