The electric field at a point P which is at a distance `l` on the perpendicular bisector of a uniformly charged wire of length `1` , charge `Q=(Q)/(2 pi varepsilon_(0)l^(2)sqrt(k))` where `k` = ?

Find the electric field at point P (as shown in figure) on the perpendicular bisector of a uniformly charged thin wire of length L carrying a charge Q. The distance of the point P from the centre of the rod is a =sqrt3/2L .

The electric foield at a point A on the perpendicular bisector of a uniformly charged wire of length l=3m and total charge q = 5 nC is x V/m. The distance of A from the centre of the wire is b = 2m. Find the value of x.

Find the electric field at a point P on the perpendicular bisector of a uniformly charged rod. The lengthof the rod is L, the charge on it is Q and the distance of P from the centre of the rod is a.

Find : (i)Electric field intensity due to an infinitely long uniformly charged, straight conductor , at a perpendicular distance d from rod. (ii)Electric field intensity at a point on perpendicular bisector of uniformly charged rod of length l and charge Q at a distance d from the centre of rod.

Electric field at a point of distance r from a uniformly charged wire of infinite length having linear charge density lambda is directly proportional to

" Electric field intensity due to a point charge " "q" ' at a distance 'r' from it is "

Calculate the potential at a point on the perpendicular bisector of uniformly charged thin rod (linear density of charge = lambda ) of length 2l at a distance a from the centre of the rod.

The magnetic field due to current in a straight wire segment of length L at a point on its perpendicular bisector at a distance r ( r gt gt L)